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5x^2+30x-360=0
a = 5; b = 30; c = -360;
Δ = b2-4ac
Δ = 302-4·5·(-360)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-90}{2*5}=\frac{-120}{10} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+90}{2*5}=\frac{60}{10} =6 $
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